Respuesta :

in the given triangles,

[tex]\frac{AC}{AB}=\frac{FD}{DE}[/tex][tex]\begin{gathered} \frac{10}{y}=\frac{15}{9} \\ y=6 \end{gathered}[/tex]

also,

[tex]\begin{gathered} \frac{AC}{CB}=\frac{FD}{FE} \\ \frac{10}{8}=\frac{15}{x} \\ x=12 \end{gathered}[/tex]

as both the triangles are congruent,

so m