Respuesta :
1) List the known and unkown values
Initial conditions
Volume: 1.7 L
Pressure: 1.2 atm
Temperature: 20ºC
Final conditions
Volume: 1.1 L
Temperature: 90ºC
Pressure:
2) Set the equation
[tex]\frac{P1V1}{T1}=\frac{P2V2}{T2}[/tex]3) Convert Celsius to Kelvin
[tex]K=ºC+273.15[/tex]Initial temperature
[tex]K=20ºC+273.15=293.15\text{ }K[/tex]Final temperature
[tex]K=90ºC+273.15=363.15\text{ }K[/tex]4) Plug in the known values
[tex]\frac{(1.2\text{ }atm)*(1.7\text{ }L)}{293.15\text{ }K}=\frac{(P2)*(1.1\text{ }L)}{363.15\text{ }K}[/tex].
[tex](\frac{(1.2\text{ }atm)*(1.7\text{ }L)}{293.15\text{ }K})*363.15\text{ }K=(\frac{(P2)*(1.1\text{ }L)}{363.15\text{ }K})*363.15\text{ }K[/tex][tex](\frac{(1.2\text{ }atm)*(1.7\text{ }L)}{293.15\text{ }K})*363.15\text{ }K=(P2)*(1.1\text{ }L)[/tex]
.
[tex](\frac{(1.2\text{ }atm)*(1.7\text{ }L)*(363.15\text{ }K)}{293.15\text{ }K})*\frac{1}{1.1\text{ }L}=\frac{(P2)*(1.1\text{ }L)}{1.1\text{ }L}[/tex].
[tex]P2=\frac{(1.2\text{ }atm)*(1.7\text{ }L)*(363.15\text{ }K)}{(293.15\text{ }K)*(1.1\text{ }L)}=2.297\text{ }atm[/tex]The new pressure in the coffee thermos is 2.3 atm.
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