Find the currents through the 8 Ω resistor at the instant that the switch is closed.0.545 A0.744 A0.641 A0.926 A

From the figure,
The resistors are in series
Thus the equiva;ent resistance is:
R=14+8=22 ohm
Thus the current through the equivalent resistance is:
[tex]i=\frac{V}{R}=\frac{12^{}}{22}=0.545\text{ A}[/tex]The answer is 0.545 A