These marbles are placed in a bag and twoof them are randomly drawn.What is the probability of drawing two yellowmarbles if the first one is NOT placed back intothe bag before the second draw?

Given the figure of marbles:
As shown, the number of marbles = 10
Two marbles are randomly drawn
We will find the probability of drawing two yellow marbles
The probability the first marble is yellow:
The number of yellow marbles = 2
so, the probability the first marble is yellow = 2/10 = 1/5
The first one is NOT placed back into the bag before the second draw
So, the number of marbles = 10 - 1 = 9
The number of yellow marbles = 2 - 1 = 1
So, the probability the second marble is yellow = 1/9
So, the probability of drawing two yellow =
[tex]\frac{1}{5}\times\frac{1}{9}=\frac{1}{45}[/tex]So, the answer will be 1/45