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A flask has a volume of 250 mL. It is filled with N2 gas at a temperature of 32°C and the pressure is found to be 1.56 atm. The number of moles of N2 (g) in the flask is equal to ___. (R = 0.0821 L. Atm/mol.k) Can someone explain how to do this??

Respuesta :

Answer:

0.0156moles

Explanations:

According to the ideal gas equation:

[tex]PV=nRT[/tex]

where;

• P is the ,pressure ,of the gas (in atm)

,

• V is the ,volume ,of the gas (in L)

,

• n is the number of moles

,

• R is the ,Gas constant

,

• T is the temperature (in K)

Given the following parameters

P = 1.56atm

V = 250mL = 0.25L

R = 0.0821 L. Atm/mol.k

T = 32 + 273 = 305K

Substitute the given parameters into the formula

[tex]\begin{gathered} n=\frac{PV}{RT} \\ n=\frac{1.56\times0.25}{0.0821\times305} \\ n=\frac{0.39}{25.04} \\ n=0.0156moles \\ \end{gathered}[/tex]

Hence the required number of moles of N2 is 0.0156moles

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