A man gets a job with a salary of $32,200 a year.He is promised a $2,250 raise each subsequent year.During a 8-year period his total earnings are $

Given
number of years, n = 8
common difference, d = 2250
starting salary, a = 32200
Find
Earnings after 8 years
Explanation
We know sum of n terms is given by
[tex]\begin{gathered} S_n=\frac{n}{2}[2a+(n-1)d] \\ =\frac{8}{2}[2(32200)+7(2250)] \\ =4(64400+15750) \\ =4(80150) \\ =320600 \end{gathered}[/tex]Final Answer
Earnings after 8 years is $320600