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Use the discriminant to find the nature of the solutions to the following quadratic equation:-4x^2+40x-100=0 Two imaginary-number solutionsTwo different rational-number solutionsOne repeated irrational-number solutionsTwo different irrational-number solutionsOne repeated rational-number solutions

Respuesta :

The given expression is

[tex]-4x^2+40x-100=0[/tex]

The discriminant is

[tex]b^2-4ac[/tex]

When a = -4, b = 40, and c = -100. Let's replace these values.

[tex](40)^2-4(-4)(-100)=1600-1600=0[/tex]

Since the discriminant is zero, we deduct that the equation has one unique solution.

Therefore, the answer is E.

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