Respuesta :
The Point-Slope form of an equation of the line, is:
[tex]y-y_1=m\mleft(x-x_1\mright)[/tex]Where "m" is the slope and this is a point of the line:
[tex](x_1,y_1)[/tex]The formula for calculate the slope, is:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]In this case, you can set up that:
[tex]\begin{gathered} y_2=6 \\ y_1=3 \\ x_2=2 \\ x_1=0 \end{gathered}[/tex]Substituting values, you get that the slope of the line is:
[tex]\begin{gathered} m=\frac{6-3}{2-0} \\ \\ m=\frac{3}{2} \end{gathered}[/tex]Knowing the slope and the point (2,6), you can susbtitute values into the equation in Point-Slope form shown at the beginning of the explanation.
Therefore, the answer is:
[tex]y-6_{}=\frac{3}{2}(x-2)[/tex]