The correct option is D.
The value of r for the given complex number is calculated below:
[tex]r=\sqrt[]{0^2+3^2}=\sqrt[]{9}=3[/tex]
now,
[tex]\tan \theta=\frac{3}{0}=\text{ not defined}[/tex]
Since the complex number lies on the positive y-axis.
[tex]\theta=\frac{\pi}{2}[/tex]
Therefore, the polar form of the given complex number is
[tex]3(\cos \frac{\pi}{2}+i\sin \frac{\pi}{2})[/tex]
