Given:
[tex]6x\text{ + }\frac{1}{4}(4x\text{ + 8) > 12}[/tex]
First, let's open the bracket:
[tex]\begin{gathered} 6x\text{ + }\frac{1}{4}\times\text{ 4x + }\frac{1}{4}\times8\text{ > 12} \\ 6x\text{ + x + 2 > 12} \end{gathered}[/tex]
Collect like terms:
[tex]\begin{gathered} 6x+x\text{ > 12 - 2} \\ 7x\text{ > 10} \end{gathered}[/tex]
Divide both sides by 7:
[tex]\begin{gathered} \frac{7x}{7}\text{ > }\frac{10}{7} \\ x\text{ > }\frac{10}{7} \end{gathered}[/tex]
Solution:
x > 10/7
