Solution
The interior angles of a quadrilateral measure to 360 degrees
Two of them are known and are 210 and 82. They add to 292 degrees.
The other two angles must sum to (360-292)=68 degrees.
They are in a ratio of 7:10
The sum of these two numbers is 17
[tex]\frac{68}{17}=4[/tex][tex]\begin{gathered} 7\times4=28^0 \\ 10\times4=40^0 \end{gathered}[/tex]
The other two angles are 28 and 40 degrees respectively.
The sum of all 4 angles is 360 degrees.
The final answer
The other two angles are 28 and 40 degrees respectively.
