The area of a trapezoid is the average of the bases multiplied by the height
[tex]\begin{gathered} A=\frac{a+b}{2}\cdot h \\ \text{ Where} \\ a\colon\text{ long base} \\ b\colon\text{ short base} \\ h\colon\text{ height} \end{gathered}[/tex]
So, in this case, you have
[tex]\begin{gathered} \\ a=16\operatorname{cm} \\ b=12\operatorname{cm} \\ h=8\operatorname{cm} \\ A=\frac{a+b}{2}\cdot h \\ A=\frac{16cm+12\operatorname{cm}}{2}\cdot8\operatorname{cm} \\ A=112\operatorname{cm}^2 \end{gathered}[/tex]
Therefore, the area of a trapezoid with these dimensions is 112 square centimeters.
