INFORMATION:
We have the next system of linear inequalities
[tex]\begin{cases}3x-y\leq2{} \\ x+7y\leq{4}\end{cases}[/tex]
And we must find the point in the options which is not a solution
STEP BY STEP EXPLANATION:
To find it, we must replace the points in the system:
- (0, -1):
[tex]\begin{gathered} 3(0)-(-1)\leq2 \\ 0+1\leq2 \\ 1\leq2 \end{gathered}[/tex]
[tex]\begin{gathered} 0+7(-1)\leq4 \\ -7\leq4 \end{gathered}[/tex]
The two inequalities are true, so the point (0, -1) is a solution to the system
- (-1, -6):
[tex]\begin{gathered} 3(-1)-(-6)\leq2 \\ -3+6\leq2 \\ 3\leq2 \end{gathered}[/tex]
Since 3 ≤ 2 is false, the point (-1, -6) is not a solution to the system
ANSWER:
(-1, -6)
