Given the rational function;
[tex]f(x)=\frac{3x+4}{x(x-2)}[/tex]
To determine the constraint for this function, we shall set the denominator equal to zero;
[tex]\begin{gathered} x(x-2)=0 \\ \text{Hence;} \\ x=0 \\ x-2=0 \\ x=2 \end{gathered}[/tex]
This means the equation does not exist when x = 0, and when x = 2.
ANSWER:
The correct answer is option C.
