Given: The thickness of a dime and a dollar as shown below
[tex]\begin{gathered} T_{\text{hickness of dime}}=0.135cm \\ T_{\text{hickness of a dollar}}=1.0922\times10^{-2}cm \end{gathered}[/tex]
To Determine: How many times thicker is the dime than the dollar bill
Solution:
Step 1: Convert the thickness of the dollar bill from standard form to ordinary form
[tex]1.0922\times10^{-2}=0.010922cm[/tex]
Step 2: Divide the thickness of the dime by the thickness of the dollar bill
[tex]\begin{gathered} \frac{0.135cm}{0.010922cm} \\ =12.36 \\ \approx12 \end{gathered}[/tex]
Hence, the dime is about 12 times thicker than the dollar bill
