Given
[tex]h(x)=(2x+4)^2[/tex]
1) x=-2,
[tex]\begin{gathered} h(-2)=(2(-2)+4)^2=(-4+4)^2=0^2=0 \\ \Rightarrow h(-2)=0 \end{gathered}[/tex]
2) x=0,
[tex]\begin{gathered} h(0)=(2\cdot0+4)^2=4^2=16 \\ \Rightarrow h(0)=16 \end{gathered}[/tex]
3) x=1
[tex]h(1)=(2\cdot1+4)^2=6^2=36[/tex]
