Given:
Liam and John together have 47 video games.
[tex]\text{Probability that they choose choose=}\frac{^2C_2}{^{47}C_2}[/tex][tex]=\frac{1}{\frac{47!}{45!2!}}[/tex][tex]=\frac{45!2!}{47!}[/tex][tex]=\frac{45!2!}{47\times46\times45!}[/tex][tex]=\frac{2}{47\times46}[/tex][tex]=\frac{1}{1081}[/tex]