Answer:
2.25
Explanation:
The expected value can be calculated as:
[tex]E(x)=x_1P(x_1)+x_2P(x_2)+\cdots+x_5P(x_5)[/tex]
Where x1, x2, x3, x4, and x5 are the different values that the variable x can take and P(x1), P(x2), P(x3), P(x4), P(x5) are their respective probabilities.
Therefore, the expected value will be equal to:
[tex]\begin{gathered} E(x)=0(0.10)+1(0.15)+2(0.35)+3(0.25)+4(0.1)+5(0.05) \\ E(x)=0+0.15+0.7+0.75+0.4+0.25 \\ E(x)=2.25 \end{gathered}[/tex]
So, the answer is 2.25
