Given:
[tex]\begin{gathered} f(x)=\frac{x-7}{x} \\ g(x)=x^2+8 \end{gathered}[/tex]
Therefore,
[tex]\begin{gathered} (g\circ f)(-1)=g(f(x))(-1)=(\frac{x-7}{x})^2+8=(\frac{-1-7}{-1})^2+8=(\frac{-8}{-1})^2+8=64+8 \\ (g\circ f)(-1)=72 \end{gathered}[/tex]
Hence, the answer is
[tex](g\circ f)(-1)=72\text{ \lparen Option 5\rparen}[/tex]
