ANSWER:
10.58 Nm
STEP-BY-STEP EXPLANATION:
Given:
Area (A) = 2.936 m²
Current (i) = 6.488 A
Magnetic field (B) = 1.108 T
Angle (θ)= 59.914°
To calculate the torque we must resort to the following formula:
[tex]\begin{gathered} \tau=MB\sin\alpha \\ \\ \alpha=90\degree-\theta=90-59.914\degree \\ \\ \alpha=30.086\degree \end{gathered}[/tex]We need to know the magnetic moment, as follows:
[tex]\begin{gathered} M=NIA \\ \\ M=1\cdot6.488\cdot2.936 \\ \\ M=19.05\text{ A}\cdot m^2 \end{gathered}[/tex]In this way we can calculate the torque:
[tex]\begin{gathered} \tau=19.05\cdot1.108\cdot\sin(30.086\degree) \\ \\ \tau=10.58\text{ Nm} \end{gathered}[/tex]Therefore, the magnitude of the torque on the loop is 10.58 Nm
