The solution of x for the equation [tex]\sqrt{3x - 4} = 2\sqrt{x-5}[/tex] is x = 16.
Given,
The equation; [tex]\sqrt{3x-4} =2\sqrt{x-5}[/tex]
We have to solve this equation to get the value of x.
That is,
[tex]\sqrt{3x-4} =2\sqrt{x-5}[/tex]
Square both sides to remove square root.
[tex]\sqrt{3x-4} ^{2} = (2\sqrt{x-5} )^{2}[/tex]
We get,
3x - 4 = 4 (x - 5)
That is,
3x - 4 = 4x - 20
Here,
20 - 4 = 4x - 3x
Then,
x = 16
That is,
The solution of x for the equation [tex]\sqrt{3x - 4} = 2\sqrt{x-5}[/tex] is x = 16.
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