Ok, we have this data:
|m| = 40 and theta = 128°
So, we are going to find the x and y-component of the vector.
So, finding x-component:
[tex]V_X=40\text{ Cos(128)=}-24.6[/tex]Finding y-component:
[tex]V_y=40\text{ Sin (128)=31.5}[/tex]The answer is aproximately (-24.6, 31.5).