The area of the figure will be the area of the rectangle, plus the area of the triangle, so:
For the rectangle:
[tex]\begin{gathered} Ar=w\cdot l \\ where\colon \\ w=12 \\ l=24 \\ Ar=(12)(24)=288in^2 \end{gathered}[/tex]For the triangle:
[tex]\begin{gathered} At=\frac{b\cdot h}{2} \\ where\colon \\ b=12 \\ h=12 \\ At=\frac{12\cdot12}{2} \\ At=72in^2 \end{gathered}[/tex]Therefore, the area is:
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