Remember that
The compound interest formula is equal to
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is the number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
r=1.21%=0.0121
P=$4,300
t=2 years
n=1
substitute in the formula above
[tex]A=4,300(1+\frac{0.0121}{1})^{1*2}[/tex][tex]\begin{gathered} A=4,300(1.0121)^2 \\ A=\$4,404.69 \end{gathered}[/tex]