Problem
what is f(x)/g(x) when f(x) = 6x3 – 19x2 + 16x – 4 and g(x) = x - 2?
Solution
We can use the long division and we have:
[tex]\frac{6x^3-19x^2+16x-4}{x-2}=6x^2+\frac{-7x^2+16x-4}{x-2}[/tex]We can simplify the last expression on this way:
[tex]6x^2+\frac{-7x^2+16x-2}{x-2}=6x^2-7x+\frac{2x-4}{x-2}=6x^2-7x+2[/tex]And the best solution for this case would be:
6x^2 - 7x + 2
