Respuesta :
The concentration of H3O+ in the solution is 6.667*10^-11M.
1st) From the dissociation equation of NaOH we calculate the concentration of OH- in the 0.0150M solution:
[tex]\text{NaOH }\rightarrow Na^{1+}+OH^{-1}[/tex]According to the equation, from 1 mol of NaOH we obtain 1 mol of OH-, so from the 0.0150M solution, we will obtain a 0.0150M concentration of OH-.
2nd) Using the Kw formula and replacing the values, we can calculate the H3O+ concentracion:
[tex]\begin{gathered} K_w=\lbrack H_3O^+\rbrack\cdot\lbrack OH^-\rbrack \\ 100\cdot10^{-14}=\lbrack H_3O^+\rbrack\cdot0.0150M \\ \frac{100\cdot10^{-14}}{0.0150M}=\lbrack H_3O^+\rbrack \\ 6.667\cdot10^{-11}=\lbrack H_3O^+\rbrack \end{gathered}[/tex]So, the concentration of H3O+ in the solution is 6.667*10^-11M.
