Given P(A) = 0.68, P(B) = 0.5 and P(A|B) = 0.91, find the value ofP(An B), rounding to the nearest thousandth, if necessary.

Remember that
[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}[/tex]Thereby,
[tex]P(A\cap B)=P(A|B)\cdot P(B)[/tex]Using the data given,
[tex]P(A\cap B)=0.455[/tex]