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four inches of a (somewhat magnified ) ruler is shown. use the ruler to give the length of the gray bar, to the nearest sixteenth of an in. write answer as a mixed #. (simplify as much as possible)

four inches of a somewhat magnified ruler is shown use the ruler to give the length of the gray bar to the nearest sixteenth of an in write answer as a mixed si class=

Respuesta :

We have the following:

We have that 4 is equal to 64/16

[tex]\frac{4\cdot16}{1\cdot16}=\frac{64}{16}[/tex]

Thefore:

The bar is found in 2 and 15 more lines, each line is 1/16

[tex]\frac{2\cdot16}{1\cdot16}+\frac{15}{16}=\frac{32}{16}+\frac{15}{16}=\frac{47}{16}=2\frac{15}{16}[/tex]

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