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At a cricket match the snack bar sells hotdogs for five dollars and nachos for four dollars the snack bar so 71 hotdogs and nachos altogether for $317 what is the total number of hotdogs soldAdd a cricket match the snack bar sells hotdogs for five dollars and nachos for four dollars the snack bar sold 71 hotdogs and nachos all together for $317 what is the total number of hotdogs sold

Respuesta :

Let x and y be the number of hotdogs and nachos that had been sold, respectively. Therefore,

[tex]5x+4y=317[/tex]

Furthermore,

[tex]x+y=71[/tex]

Then, solving for x, x=71-y.

Substitute into the first equation,

[tex]\begin{gathered} \Rightarrow5(71-y)+4y=317 \\ \Rightarrow355-5y+4y=317 \\ \Rightarrow y=38 \end{gathered}[/tex]

And, solving for x,

[tex]\begin{gathered} \Rightarrow x=71-38=33 \\ \Rightarrow x=33 \end{gathered}[/tex]

33 hotdogs were sold.