Given:
Three dice are rolled.
Required:
Find the probability of getting a 2, a 3, and a 4.
Explanation:
Three dice are rolled simultaneously then the number of total outcomes = 6 x 6x 6 =216
The number of possible outcomes of 2 = 1
The number of possible outcomes of 3 = 1
The number of possible outcomes of 4 = 1
The probability of an event is given by the formula:
[tex]P=\frac{Number\text{ of possible outcomes}}{Total\text{ outcomes}}[/tex][tex]\begin{gathered} P(2)=\frac{1}{6} \\ P(3)=\frac{1}{6} \\ P(4)=\frac{1}{6} \end{gathered}[/tex]The probability of getting a 2, a 3, and a 4 are:
[tex]\begin{gathered} P(2,3,4)=\frac{1}{6}\times\frac{1}{6}\times\frac{1}{6}\times3 \\ P(2,3,4)=\frac{3}{216} \end{gathered}[/tex]Final Answer:
Option third is the correct answer.
