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2 Na + Cl2 --> 2 NaCl21 mol Na reacts with 21 mol Cl2 to produce NaCl. If a student carries out this procedure and obtains 6 mol of the theoretical 21 mols of NaCl, what is his percent yield?Enter your answer as a whole number: ______ %

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Answer

%Yield = 29%

Explanation

Given

2 Na + Cl2 --> 2 NaCl

moles of Na = 21 mol

moles of Cl2 = 21 mol

theoretical moles of NaCl = 21 moles

actual moles of NaCl = 6 moles

Solution

%Yield = actual/theoretical x 100

%Yield = 6 mol/21 mol x 100

%Yield = 29%

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