Answer:
0 m/s per second
Explanation:
To determine the magnitude of acceleration (in m/s per second) of the object between 2 s and 6s, we would calculate the rate of change over the given interval which s expressed as
rate of change = (y2 - y1)/(x2 - x1)
From the information given,
x1 = 2, y1 = 4
x2 = 6, y2 =4
Thus,
rate of change = (4 - 4)/(6 - 2) = 0/4 = 0
Thus, the magnitude of acceleration (in m/s per second) of the object between 2 s and 6s is 0 m/s per second
