Given,
[tex]\begin{gathered} d_1=6+12\text{ } \\ \text{ = 18 feet} \end{gathered}[/tex][tex]\begin{gathered} d_2=5+5 \\ \text{ = 10 feet} \end{gathered}[/tex]
Area of the kite formula
[tex]\begin{gathered} A=\frac{1}{2}\times d_1\times d_2 \\ \text{ }=\frac{1}{2}\times18_{}\times10 \\ \text{ =90 feet}^2 \end{gathered}[/tex]
The area of the kite is 90 ft^2
the answer is option A
