Let
m1= 10 kg
m2= 6 kg
Distance of m2 from pivot = 4 m
Distance of m1 from pivot = x
Procedure
If system is not rotating then it should be in equilibrrium position.
[tex]\begin{gathered} m_1g_{}x=m_2gd_2 \\ x=\frac{m_2d_2}{m_1} \\ x=\frac{6kg\cdot4m}{10kg} \\ x=2.4m \end{gathered}[/tex]
the 10 kg mass is 2.4m away from the pivot
