Answer:
[tex]T_i\text{ = 364}\degree C[/tex]Explanation:
Here, we want to get the initial temperature of the copper piece
Mathematically:
[tex]Heat\text{ loss by copper = Heat gained by water}[/tex]
The amount of heat lost or gained by any substance can be calculated as:
[tex]q\text{ = mc}\Delta T[/tex]where:
m represents the mass
c represents the specific heat capacity (heat capacity of water is 4.184 J/g.C)
delta T represents the temperature change
Substituting the values, we have it that:
[tex]240\times0.39\text{ }\times\text{ \lparen T}_i-42)\text{ = 400}\times4.184\text{ }\times(42-24)[/tex][tex]\begin{gathered} 93.6(T_i-42)\text{ = 30124.8} \\ T_i-42\text{ = }\frac{30124.8}{93.6} \\ \\ T_I-42\text{ = 321.85} \\ T_i\text{ =321.85 + 42} \\ T_i\text{ = 364}\degree C \end{gathered}[/tex]