The radioactive isotope 14C has a half-life of approximately 5715 years. Now there are 50g of 14C.(1) How much of it remains after 1600 years? (Round your answer to three decimal places.) g Tries 0/99(2) How much of it remains after 16000 years? (Round your answer to three decimal places.) g Tries 0/99

The radioactive isotope 14C has a halflife of approximately 5715 years Now there are 50g of 14C1 How much of it remains after 1600 years Round your answer to th class=

Respuesta :

Given

The half life is T=5715 years

The initial amount is N=50 g

To find

1) How much of it remains after 1600 years?

(2) How much of it remains after 16000 years?

Explanation

The amount of carbon remains after t yaers is

[tex]N^{\prime}=N(\frac{1}{2})^{\frac{t}{T}}[/tex]

1. Thus putting t=1600 years

[tex]\begin{gathered} N^{\prime}=50(\frac{1}{2})^{\frac{1600}{5715}} \\ \Rightarrow N^{\prime}=41.208\text{ g} \end{gathered}[/tex]

2.Putting t=16000

[tex]\begin{gathered} N^{\prime}=50(\frac{1}{2})^{\frac{16000}{5715}} \\ \Rightarrow N^{\prime}=7.184\text{ g} \end{gathered}[/tex]

Conclusion

1.Amount remains after 1600 year is 41.208 g

2.Amount remains after 16000 year is 7.184 g