Solution
For this case we can use the following formula:
[tex]I=Pr(\frac{days}{360})[/tex]Then we can replace the following values:
P= 52610 , r= 0.085 , days= 82
We are assuming a 360 days for a year, and we have:
[tex]I=52610\cdot0.085\cdot(\frac{82}{360})=1018.59[/tex]Then the answer for this case is:
1018.19$
