0.171moles
According to the ideal gas equation;
[tex]PV=nRT[/tex]where:
• P is the, pressure ,in atm
,• V is the ,volume ,in litres
,• n is the ,number of moles ,of gas
,• R is the, boltzmann constant
,• T is the, temperature ,in Kelvin
Given the following parameters
P = 2.5atm
V = 1.67L
T = 25.0°C = 25 + 273 = 298K
R = 0.08205Latm/molK
Substitute the given parameters into the formula
[tex]\begin{gathered} n=\frac{PV}{RT} \\ n=\frac{2.5\times1.67}{0.08205\times298} \\ n=\frac{4.175}{24.4509} \\ n=0.171mole \end{gathered}[/tex]Hence the amount of moles of nitrous oxide gas used is 0.171moles