Answer:
0. 6x+20
,
1. 15x+25 square feet
,
2. 200 square feet
,
3. 175 square feet
,
4. $218.75
Explanation:
Part 1
The length of the pool with the tile = 2x+5 ft
The width of the pool with the tile = x+5 ft
[tex]\begin{gathered} \text{Perimeter}=2(l+w) \\ =2(2x+5+x+5) \\ =2(3x+10) \\ =6x+20\text{ ft} \end{gathered}[/tex]
Part 2 (The area of just the tile)
[tex]\begin{gathered} \text{Area of just the tile = Area of the outer rectangle - Area of the pool} \\ =(2x+5)(x+5)-(2x)(x) \\ \text{Expand} \\ =2x^2+10x+5x+25-2x^2 \\ =15x+25\text{ square feet} \end{gathered}[/tex]
Part 3
If x=10
[tex]\text{Area of the pool}=(2x)(x)=(2\times10)(10)=200ft^2[/tex]
Part 4
From part 2, the area of the tiles = 15x+25
If x=10
[tex]\text{Area of the tile}=15(10)+25=150+25=175ft^2[/tex]
Part 5
The area of the tile = 175 square foot
If the tile costs $1.25 per square foot
The amount needed to replace the tiles will be:
[tex]175ft^2\times\frac{\$1.25}{ft^2}=\$218.75[/tex]
