Answer:
[tex]2,644.80\text{ mmHg}[/tex]Explanation:
Here, we want to get the pressure occupied in the gas tank
Mathematically, we can use the ideal gas equation to find this out as follows:
[tex]\begin{gathered} PV\text{ = nRT} \\ P\text{ = }\frac{nRT}{V} \end{gathered}[/tex]where:
P is the pressure in mmHg which we want to calculate
V is the volume which is 20 L
R is the molar gas constant which is 0.0821 L.atm/mol.K
T is the temperature in Celsius which we have to convert to Kelvin by adding 273 (273 + 23 = 296 K)
n is the number of moles which is 2.86 mol
Substituting the values, we have it that:
[tex]P\text{ = }\frac{2.86\times0.0821\times296}{20}\text{ = 3.48 atm}[/tex]Now, we have to convert this to mmHg
To do this, we have to multiply the atm value by 760 mmHg
We have that as:
[tex]3.48\text{ }\times\text{ 760 = 2,644.80 mmHg}[/tex]