The given function is
[tex]f(x)=-\frac{1}{4}(x+1)^2+4[/tex]Given that the function is in standard form f(x) = a(x-h)2 + k, we can deduct that the vertex is V(-1, 4), where h = -1 and k = 4.
Remember that the standard form already shows the vertex, so we don't have to calculate it, just observe it in the standard form function.
The axis of symmetry would be x = -1.
The graph is shown below.
