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Ms. Lee bought some Reese's and a bag of chips. They cost $4.36 altogether. The chips cost $1.60 more than the Reese's.How much did the Reese's cost? (Hint: it's not as simple as subtracting the two numbers)

Respuesta :

Let x be the price of the reese's. Since we know that the chips cost $1.6 more that means that its price is:

[tex]x+1.6[/tex]

Now, both things had a cost of 4.36, then we have:

[tex]x+(x+1.6)=4.36[/tex]

Solving for x we have:

[tex]\begin{gathered} x+(x+1.6)=4.36 \\ 2x+1.6=4.36 \\ 2x=4.36-1.6 \\ 2x=2.76 \\ x=\frac{2.76}{2} \\ x=1.38 \end{gathered}[/tex]

Therefore the cost of the reese's is $1.38.

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