First let's state the standard form of the quadratic equation:
[tex]y=ax^2+bx+c[/tex]Where c is the y-intercept.
Now, let's put the function F(x) in the standard form:
[tex]\begin{gathered} f(x)=2(x+3)^2-6 \\ f(x)=2(x^2+6x+9)-6 \\ f(x)=2x^2+12x+18-6 \\ f(x)=2x^2+12x+12 \end{gathered}[/tex]Comparing the function with the model, we have c = 12, therefore the y-intercept is equal 12.
