The first step to answer this question is to convert the given gallons to liters and then to mililites using the given conversion factors:
[tex]5.28gal\cdot\frac{3.785L}{1gal}\cdot\frac{1000mL}{1L}=19984.8mL[/tex]The second step is to convert the volume of water to mass using its given density:
[tex]19984.8mL\cdot\frac{1.00g}{mL}=19984.8g[/tex]Finally, use the following formula to find the heat needed to raise the temperature of water:
[tex]Q=Cp\cdot m\cdot\Delta T[/tex]Where Q is the heat, Cp is the specific heat, m is the mass and ΔT is the difference of temperatures. Replace for the given values and find Q:
[tex]\begin{gathered} Q=4.184J/g\degree C\cdot19984.8g\cdot(88\degree C-25\degree C) \\ Q=5,267,833.4J \end{gathered}[/tex]It means that the heat needed to raise the temperature of water is 5267833.4J.
