Respuesta :
The acid dissociation constant Ka is 1.52 × [tex]10^{-5}[/tex].
Acid dissociation constant:
Ka or the acid dissociation constant is the value that differentiates the weak and strong acids from each other and tells about the dissociation of the acid in the solution.
Dissociation of acid is:
HA ----> [tex]H^{+}[/tex] + [tex]A^{-}[/tex]
Initially, the concentration of the reaction is c and the final reaction is 0.
In the equilibrium, the concentration of the reactant is c( 1 - α ) and the final reaction is cα.
The dissociation constant formula:
[tex]K_{a}[/tex] = cα × cα / c( 1 -α)
We know that [[tex]H^{+}[/tex]] = cα.
pH = -log[[tex]H^{+}[/tex]]
It is given that:
pH = 2.81
The concentration of hydrogen ions is 1.5 × [tex]10^{-3}[/tex]
Substituting the value in the equation we get:
1.5 × [tex]10^{-3}[/tex] = 1.46 α
α = 0.00102
[tex]K_{a}[/tex] = (1.46 × 0.00102)² / 1.46( 1 - 0.00102)
= 0.00002204/ 1.458
= 0.0000152
= 1.52 × [tex]10^{-5}[/tex]
Therefore Ka is 1.52 ×[tex]10^{-5}[/tex]
To know more about the acid dissociation constant refer to the link given below:
https://brainly.com/question/22668939
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