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the diameters of ball bearings are distributed normally. the mean diameter is 139 millimeters and the variance is 36. find the probability that the diameter of a selected bearing is greater than 152 millimeters. round your answer to four decimal places.

Respuesta :

The probability that the diameter of a selected bearing is greater than 152 millimeters is 64.05%.

What is termed as the z-score?

  • The Z-score indicates how far the measure deviates from the mean.
  • After determining the Z-score, we examine the z-score table to determine the p-value affiliated with this z-score.
  • This p-value represents the probability that the measure's value is less than X, or the percentile of X.

For the given question;

The data for the ball bearing is given as-

  • mean diameter μ = 139 millimeters
  • variance σ = 36  millimeters
  • sample mean x =  152 millimeters

Z-score = (x - μ)/σ

Put the values;

z = (152 - 139)/36

z = 0.36

P(x > 125) = P(z > 0.36), see p values from z table for 0.36.

P(x > 125) = 0.6405

P(x > 125) = 64.05%

Thus, the probability that the diameter of a selected bearing is greater than 152 millimeters is 64.05%.

To know more about the z-score, here

https://brainly.com/question/15333077

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