The probability that the coin lands on heads (3-√3)/6.
For the given question;
Let x represent the likelihood of flipping heads. As a result, the probability of tossing tails is (1-x).
The probability of tossing two heads and two tails is equivalent to the number of aspects to flip it multiplied by the product of a probabilities of each coin flip.
6x²(1 - x)² = 1/6
On solving,
x²(1 - x)² = 1/36
Taking square root both sides.
x(1 - x) = ±1/6
Because both x and (1-x) seem to be non negative for the preferred probability x, we only need to take into account the positive root.
x(1 - x) = 1/6
Re arranging.
6x² - 6x + 1 = 0
Find the roots of the quadratic equation using the quadratic formula as;
(3±√3)/6
Using the quadratic formula, the roots of the this equation are (3±√3)/6.
Thus, as the probability of heads becomes less than half, the answer is (3-√3)/6.
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