We will have the following:
We will determine the magnitude of the resulting force as follows:
We find the sum of forces on the x and y-axis and then we calculate the resulting force, that is:
[tex]\sum Fx=400cos(30)-250cos(70)\approx250.91[/tex][tex]\sum F_y=400sin(30)-250sin(70)\approx-34.92[/tex]Now, we find the resulting force:
[tex]F_r=\sqrt{(250.91)^2+(-34.92)^2}\Rightarrow F_r\approx253.3[/tex]So, the magnitude of the resulting force is approximately 253.3 N.
