Let be "x" the first number of the set that contains three consecutives numbers whose sum is 54. The others two numbers can be represented as:
[tex]\begin{gathered} x+1 \\ x+2 \end{gathered}[/tex]According to the exercise, when you add these three consecutives numbers, you get 54 as the result of the addition. Based on this, you can write the following equation:
[tex]x+(x+1)+(x+2)=54[/tex]Now you have to solve for "x":
[tex]\begin{gathered} x+x+1+x+2=54 \\ 3x+3=54 \\ 3x=54-3 \\ 3x=51 \\ x=\frac{51}{3} \\ x=17 \end{gathered}[/tex]Substituting this value, you get that the others numbers are:
[tex]\begin{gathered} x+1=17+1=18 \\ x+2=17+2=19 \end{gathered}[/tex]So the three numbers are:
[tex]17,18,19[/tex]The answer is the last option.
