Step 1: Angle of elevation
Step 2 : Using SOHCAHTOA
[tex]\begin{gathered} \text{Height of the building = 150ft} \\ \text{distance to the building = x} \\ \text{angle of elevation = 6}^{\circ} \\ \text{from SOHCAHTOA } \\ Tan\text{ }\theta\text{ = }\frac{\text{Opposite}}{\text{Adjacent}} \\ Tan6^0=\text{ }\frac{150ft}{x} \\ x\text{ = }\frac{150ft}{\tan 6^0} \\ x\text{ = }\frac{150ft}{0.105} \\ x\text{ = 1428.5ft} \\ \end{gathered}[/tex]Hence the distance she need to work = 1428.5 ft
